-0.15s^2+27s-200=0

Solution for -0.15s^2+27s-200=0 equation:

-0.15s^2+27s-200=0

a = -0.15; b = 27; c = -200;
Δ = b2-4ac
Δ = 272-4·(-0.15)·(-200)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{609}}{2*-0.15}=\frac{-27-\sqrt{609}}{-0.3}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{609}}{2*-0.15}=\frac{-27+\sqrt{609}}{-0.3}
$